0.197530864b^2=729-b^2

Solution for 0.197530864b^2=729-b^2 equation:

0.197530864b^2=729-b^2

We move all terms to the left:

0.197530864b^2-(729-b^2)=0

We get rid of parentheses

0.197530864b^2+b^2-729=0

We add all the numbers together, and all the variables

1.197530864b^2-729=0

a = 1.197530864; b = 0; c = -729;
Δ = b2-4ac
Δ = 02-4·1.197530864·(-729)
Δ = 3491.999999424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{3491.999999424}}{2*1.197530864}=\frac{0-\sqrt{3491.999999424}}{2.395061728}
=-\frac{\sqrt{}}{2.395061728}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{3491.999999424}}{2*1.197530864}=\frac{0+\sqrt{3491.999999424}}{2.395061728}
=\frac{\sqrt{}}{2.395061728}
$